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What to createLesson plan
Which subjectMathematics
What topicAdding and Subtracting unlike denominators
What length (min)30
What age groupYear or Grade 5
Include homework
Include images descriptions
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Lesson Plan: Adding and Subtracting Unlike Denominators

Subject: Mathematics

Grade Level: 5

Duration: 30 minutes

Topic: Adding and Subtracting Unlike Denominators


Objective

Students will learn how to add and subtract fractions with unlike denominators by finding a common denominator.

Materials Needed

Introduction (5 minutes)

  1. Engage Students: Begin the lesson with a quick review of fractions. Ask students to share examples of fractions they know and what the numerator and denominator represent.
  2. Introduce the Topic: Explain that today, they will learn how to add and subtract fractions that have different denominators, which can sometimes be challenging.

Direct Instruction (10 minutes)

  1. Finding a Common Denominator:

    • Explain the concept of a common denominator. Use two fractions as an example, such as ( \frac{1}{3} ) and ( \frac{1}{4} ).
    • Show how to find the least common denominator (LCD) by identifying the multiples of the denominators. In this case, the multiples of 3 (3, 6, 9, 12) and 4 (4, 8, 12) lead to 12 as the LCD.
  2. Example on the Board:

    • Convert each fraction to have the LCD:
      • For ( \frac{1}{3} ):
        ( \frac{1}{3} = \frac{1 \times 4}{3 \times 4} = \frac{4}{12} )
      • For ( \frac{1}{4} ):
        ( \frac{1}{4} = \frac{1 \times 3}{4 \times 3} = \frac{3}{12} )
    • Add the fractions: [ \frac{4}{12} + \frac{3}{12} = \frac{7}{12} ]
    • Subtraction example (e.g., ( \frac{3}{4} - \frac{1}{6} )):
      • Find the LCD (12).
      • Convert to have the common denominator and subtract: [ \frac{3}{4} = \frac{9}{12}, \quad \frac{1}{6} = \frac{2}{12} \quad \Rightarrow \quad \frac{9}{12} - \frac{2}{12} = \frac{7}{12} ]

Guided Practice (5 minutes)

Independent Practice (5 minutes)

Closure (5 minutes)


Homework

Instructions: Solve the following problems. Show all your work.

  1. ( \frac{2}{3} + \frac{1}{6} )
  2. ( \frac{5}{8} - \frac{3}{16} )
  3. ( \frac{1}{4} + \frac{1}{2} )

Answers:

  1. For ( \frac{2}{3} + \frac{1}{6} ):

    • Common denominator = 6: [ \frac{2}{3} = \frac{4}{6} \quad \Rightarrow \quad \frac{4}{6} + \frac{1}{6} = \frac{5}{6} ]
  2. For ( \frac{5}{8} - \frac{3}{16} ):

    • Common denominator = 16: [ \frac{5}{8} = \frac{10}{16} \quad \Rightarrow \quad \frac{10}{16} - \frac{3}{16} = \frac{7}{16} ]
  3. For ( \frac{1}{4} + \frac{1}{2} ):

    • Common denominator = 4: [ \frac{1}{2} = \frac{2}{4} \quad \Rightarrow \quad \frac{1}{4} + \frac{2}{4} = \frac{3}{4} ]

Teacher Notes