Describe in detail what you need | The graph of f(x) = -2x3 concaves upward in the entire domain. True or False |
How many pages | 1 |
In calculus, understanding the concavity of a function is essential for analyzing its behavior and determining local maxima and minima. Let's explore the concavity of the function defined by:
[ f(x) = -2x^3 ]
To analyze the concavity, we first need to find the first derivative of the function:
[ f'(x) = \frac{d}{dx}(-2x^3) = -6x^2 ]
Next, we calculate the second derivative, which will help us determine the concavity of the function:
[ f''(x) = \frac{d}{dx}(-6x^2) = -12x ]
The second derivative, ( f''(x) = -12x ), will tell us about the concavity of the function:
To determine where the second derivative changes sign, we set it equal to zero:
[ -12x = 0 \implies x = 0 ]
Now we need to test the sign of the second derivative in the intervals created by the critical point ( x = 0 ):
For ( x < 0 ):
For ( x > 0 ):
Given that:
We can conclude that the assertion that the graph of ( f(x) = -2x^3 ) concaves upward in the entire domain is False. The function is not concave up everywhere; it exhibits a change in concavity at ( x = 0 ).
False: The graph of ( f(x) = -2x^3 ) does not concave upward in the entire domain; it is concave down for ( x > 0 ).