aidemia--modules-lessonplan_request | Titles of parts of the lesson must be formatted as headings |
What to create | Lesson plan |
Which subject | Mathematics |
What topic | Statistics |
What length (min) | 30 |
What age group | Year or Grade 11 |
Include homework | |
Include images descriptions | |
Any other preferences |
30 minutes
Begin the lesson by asking students what they know about statistics.
Mean
[ \text{Example} : \text{Find the mean of the data set } [3, 7, 5, 10] ] [ \text{Mean} = \frac{3 + 7 + 5 + 10}{4} = \frac{25}{4} = 6.25 ]
Median
[ \text{Example} : \text{Find the median of the data set } [2, 3, 5, 9, 12] ]
Mode
[ \text{Example} : \text{Find the mode of the data set } [4, 1, 2, 4, 3, 5, 3, 4] ]
Range
[ \text{Example} : \text{Find the range of the data set } [15, 20, 10, 30] ] [ \text{Range} = 30 - 10 = 20 ]
For the following data set: [6, 7, 2, 8, 3, 6, 9, 6]
, calculate:
Create a scenario where determining the mean is more useful than the median, and explain why.
Given the dataset: [6, 7, 2, 8, 3, 6, 9, 6]
[2, 3, 6, 6, 6, 7, 8, 9]
=> Median = (\frac{6 + 6}{2} = 6)Scenario: Suppose you want to know the average score of students in a test. If the scores are highly skewed (for example, most students scored either very high or very low), the mean would be affected by the outliers more so than the median which is more representative of the actual central tendency of student performance. Therefore, using the median gives a better understanding of typical performance in such a case.
This lesson plan aligns with the New Zealand Curriculum, encouraging critical thinking and collaborative learning among Year 11 students.